And this pole gives the frequency where the 3dB-bandwidth is defined. I should add that this is a simplified explanation; a detailed explanation involves the open-loop gain Aol and its frequency response:. You're are basically correct. The derivation of the formulas can be found in multiple places e. Krenz's textbook. Okay, so I am pretty late to the party, but I just thought I would provide future ponderers with a single equation to solve this for either inverting or non-inverting amplifiers of this nature:.
The above example assumes an ideal op-amp. If you wish to find the true bandwidth of the circuit taking into consideration the effect of finite open loop gain and frequency dependence, you must consider the gain of the circuit at the -3dB point. Then the same is also true for the inverting circuit. Therefore, to answer your original question However, the bandwidth is not 5MHz, it is 7. I hope this helps. Yes, barring limitations in the external components.
To get a rough idea of minimum bandwidth, divide the opamp's gain-bandwidth-product by the absolute value of the closed loop gain. That is the same whether inverting or non-inverting. However, you also have to think about the external components. There will always be some parasitic capacitance. To get the value computed above, the R-C low pass filters formed by any resistance and some parasitic capacitance must have a rolloff comfortably above the bandwidth you want. To be pessimistic, assume 20 pF caps are added to ground and maybe 10 pF across components wherever they would reduce the bandwidth.
For example, assume 10 pF across R2 in the second example. We can work this backward and find the resistance that has 5 MHz rolloff with 10 pF, which is 3. Since you'd actually be 3 dB additional down for every filter at the rolloff frequency, you want that to be at least a octave, preferably octaves, past the frequency of interest. Sign up to join this community. The best answers are voted up and rise to the top.
Stack Overflow for Teams — Start collaborating and sharing organizational knowledge. Create a free Team Why Teams? Learn more. Bandwidth of inverting and non-inverting op-amps Ask Question. Asked 6 years, 7 months ago. Modified 5 years, 4 months ago. Viewed 23k times. Ilmari Karonen 6 6 silver badges 13 13 bronze badges. Ashik Anuvar Ashik Anuvar 2 2 gold badges 12 12 silver badges 21 21 bronze badges.
There's your answer. They are different: books. From the circuit, it can be seen that the R 2 R f in the above picture and R 1 R 1 in the above picture act as a potential divider for the output voltage and the voltage across resistor R 1 is applied to the inverting input.
When the non-inverting input is connected to the ground, i. Since the inverting input terminal is at ground level, the junction of the resistors R 1 and R 2 must also be at ground level. This implies that the voltage drop across R 1 will be zero. As a result, the current flowing through R 1 and R 2 must be zero. Thus, there are zero voltage drops across R 2 , and therefore the output voltage is equal to the input voltage, which is 0V.
When a positive-going input signal is applied to the non-inverting input terminal, the output voltage will shift to keep the inverting input terminal equal to that of the input voltage applied. Hence, there will be a feedback voltage developed across resistor R 1 ,.
The closed-loop voltage gain of a non-inverting amplifier is determined by the ratio of the resistors R 1 and R 2 used in the circuit. Practically, non-inverting amplifiers will have a resistor in series with the input voltage source, to keep the input current the same at both input terminals. In a non-inverting amplifier, there exists a virtual short between the two input terminals. A virtual short is a short circuit for voltage, but an open-circuit for current.
The virtual short uses two properties of an ideal op-amp:. Although virtual short is an ideal approximation, it gives accurate values when used with heavy negative feedback. As long as the op-amp is operating in the linear region not saturated, positively or negatively , the open-loop voltage gain approaches infinity and a virtual short exists between two input terminals. Because of the virtual short, the inverting input voltage follows the non-inverting input voltage. If the non-inverting input voltage increases or decreases, the inverting input voltage immediately increases or decreases to the same value.
In other words, the gain of a voltage follower circuit is unity. The output of the op-amp is directly connected to the inverting input terminal, and the input voltage is applied at the non-inverting input terminal. The voltage follower, like a non-inverting amplifier, has very high input impedance and very low output impedance.
The circuit diagram of a voltage follower is shown in the figure below. It can be seen that the above configuration is the same as the non-inverting amplifier circuit, with the exception that there are no resistors used. The gain of a non-inverting amplifier is given as,. So, the gain of the voltage follower will be equal to 1.
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|Cowboy vest for women||Add a comment. Modified 5 years, 4 months ago. If the same op-amp is used in both inverting and non-inverting modes with same closed loop gain using appropriate resistorswill the closed loop bandwidth of the op-amp in both cases be the same? The circuit diagram of a voltage follower is shown in the figure below. The voltage follower or unity gain buffer circuit is commonly used to isolate different circuits, i.|
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